(-3y^2+2)(y+3)=

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Solution for (-3y^2+2)(y+3)= equation:


Simplifying
(-3y2 + 2)(y + 3) = 0

Reorder the terms:
(2 + -3y2)(y + 3) = 0

Reorder the terms:
(2 + -3y2)(3 + y) = 0

Multiply (2 + -3y2) * (3 + y)
(2(3 + y) + -3y2 * (3 + y)) = 0
((3 * 2 + y * 2) + -3y2 * (3 + y)) = 0
((6 + 2y) + -3y2 * (3 + y)) = 0
(6 + 2y + (3 * -3y2 + y * -3y2)) = 0
(6 + 2y + (-9y2 + -3y3)) = 0
(6 + 2y + -9y2 + -3y3) = 0

Solving
6 + 2y + -9y2 + -3y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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